How many milliliters of a 0.266 M NaNO₃ solution are required to make 150.0 mL of 0.075 M NaNO₃ solution?

Question

Quizplus · Accepted Answer

First, we need to use the formula: M1V1 = M2V2 where: M1 = 0.266 M (the concentration of the stock solution) V1 = unknown (the volume of the stock solution we need to use) M2 = 0.075 M (the concentration we want to achieve) V2 = 150.0 mL (the final volume of the solution) Rearranging the equation, we get: V1 = (M2V2)/M1 V1 = (0.075 mol/L) x (0.150 L) / (0.266 mol/L) V1 = 0.0423 L or 42.3 mL Therefore, we need 42.3 mL of the 0.266 M NaNO₃ solution to make 150.0 mL of 0.075 M NaNO₃ solution.

How Many Milliliters of a 0