The equilibrium constant is given for one of the reactions below.Determine the value of the missing equilibrium constant.
2 HD(g) ⇌ H₂(g) + D₂(g) K_c = 0.28
2 H₂(g) + 2 D₂(g) ⇌ 4 HD(g) K_c = ?

Question

The equilibrium constant is given for one of the reactions below.Determine the value of the missing equilibrium constant. 2 HD(g)⇌ H₂(g)+ D₂(g)K_c = 0.28 2 H₂(g)+ 2 D₂(g)⇌ 4 HD(g)K_c = ?

Quizplus · Accepted Answer

The equilibrium constant for the reverse reaction is the reciprocal of the given equilibrium constant. Therefore, Kc for 2 H2(g) + 2 D2(g) ⇌ 4 HD(g) is 1/0.28 = 3.57, which is approximately 13 when considering the stoichiometry of the reaction.

The Equilibrium Constant Is Given for One of the Reactions