The K_p for the reaction below is 1.49 × 10⁸ at 100.0°C:
CO(g) + Cl₂(g) ⇌ COCl₂(g)
In an equilibrium mixture of the three gases,P_CO = P_C_l₂ = 2.22 × 10^-4 atm.The partial pressure of the product,phosgene (COCl₂) ,is ________ atm.

Question

Quizplus · Accepted Answer

The equilibrium constant expression for the reaction is:K_p = P_COCl2 / (P_CO * P_Cl2)Substituting the given values into the expression, we get:1.49 × 10⁸ = P_COCl2 / (2.22 × 10^-4 atm * 2.22 × 10^-4 atm)Solving for P_COCl2, we get:P_COCl2 = 7.34 atmTherefore, the partial pressure of phosgene in the equilibrium mixture is 7.34 atm.

The Kp for the Reaction Below Is 1

The K_p for the Reaction Below Is 1