The equilibrium constant for the reaction A(g)LB(g)is 10 2 .A reaction mixture initially contains [A] = 10.1 M and [B] = 0.0 M.Which statement is true at equilibrium?

The equilibrium constant K = [B]/[A] = 10^2 implies [B] is much larger than [A] at equilibrium. Only option B satisfies this condition.

The equilibrium constant for the reaction A(g)LB(g)is 10 2 .A reaction mixture initially contains [A] = 10.1 M and [B] = 0.0 M.Which statement is true at equilibrium?

The equilibrium constant K = [B]/[A] = 10^2 implies [B] is much larger than [A] at equilibrium. Only option B satisfies this condition.

Solved

The Equilibrium Constant for the Reaction A(g)LB(g)is 10²

Question 103

Multiple Choice

The equilibrium constant for the reaction A(g) LB(g) is 10².A reaction mixture initially contains
[A] = 10.1 M and [B] = 0.0 M.Which statement is true at equilibrium?

A) The reaction mixture contains [A] = 10.0 M and [B] = 0.10 M.
B) The reaction mixture contains [A] = 0.10 M and [B] = 10.0 M.
C) The reaction mixture contains [A] = 0.55 M and [B] = 0.55 M.
D) The reaction mixture contains [A] = 1.0 M and [B] = 100.0 M.

Correct Answer: