The equilibrium constant (Kc)for the reaction N₂O₄(g)⇌ 2 NO₂ (g)is 5.85 × 10^-3at 10°C.A reaction mixture has 0.025 M of N₂O₄and 0.033 M of NO₂at time t.What statement is correct for this reaction at time t?

Question

Quizplus · Accepted Answer

Given, Kc = 5.85 × 10^-3 at 10°C
The reaction involves the conversion of N2O4 to NO2, meaning the forward reaction is N2O4 → 2NO2, and the reverse reaction is 2NO2 → N2O4.
If Qc (reaction quotient) is less than Kc, then the reaction proceeds in the forward direction. If Qc is greater than Kc, then the reaction proceeds in the reverse direction. If Qc is equal to Kc, then the reaction is in equilibrium.
At time t, Qc = [NO2]^2/[N2O4] = (0.033 M)^2/0.025 M = 0.0436
Since Qc < Kc at time t, the reaction has not yet reached equilibrium and is proceeding in the forward direction. Therefore, the correct choice is A) The reaction goes to the left.

The Equilibrium Constant (Kc)for the Reaction N2O4(g)⇌ 2 NO2 (G)is

The Equilibrium Constant (Kc)for the Reaction N₂O₄(g)⇌ 2 NO₂ (G)is