A car is traveling with a constant speed of 30.0 m/s when the driver suddenly applies the brakes,causing the car to slow down with a constant acceleration.The car comes to a stop in a distance of 120 m.What was the acceleration of the car as it slowed down? A)3.75 m/s² B)4.00 m/s² C)4.25 m/s² D)4.50 m/s² E)4.75 m/s²

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Quizplus · Accepted Answer

The acceleration can be found using the equation $v^2 = u^2 + 2as$, where $v = 0$ (final velocity), $u = 30.0$ m/s (initial velocity), $s = 120$ m (distance), and $a$ is the acceleration. Rearranging for $a$, we get $a = -\frac{u^2}{2s}$. Substituting the given values, $a = -\frac{(30.0)^2}{2 \times 120} = -\frac{900}{240} = -3.75$ m/s$^2$. The negative sign indicates deceleration.

A Car Is Traveling with a Constant Speed of 30