A ball is thrown downward from the top of a building with an initial speed of 25 m/s.It strikes the ground after 2.0 s.How high is the building,assuming negligible air resistance?
A)20 m
B)30 m
C)50 m
D)70 m

Question

Quizplus · Accepted Answer

The height can be calculated using the formula: $ h = v_i \cdot t + \frac{1}{2} g \cdot t^2 $. Here, $ v_i = 25 \, \text{m/s} $, $ g = 9.8 \, \text{m/s}^2 $, and $ t = 2.0 \, \text{s} $. Plugging in these values gives $ h = 25 \cdot 2 + \frac{1}{2} \cdot 9.8 \cdot 2^2 = 50 + 19.6 = 69.6 \approx 70 \, \text{m} $.

A Ball Is Thrown Downward from the Top of a Building