A 3.0-kg mass and a 5.0-kg mass hang vertically at the opposite ends of a very light rope that goes over an ideal pulley.If the masses are gently released,what is the resulting acceleration of the masses? A)0.00 m/s² B)3.7 m/s² C)2.5 m/s² D)4.9 m/s² E)6.1 m/s²

Question

Quizplus · Accepted Answer

The acceleration of the masses can be determined using the formula:
a = (m2 - m1) g / (m1 + m2), where m1 and m2 are the masses and g is the acceleration due to gravity.
Substituting the given values, we get:
a = (5.0 - 3.0) kg x 9.81 m/s^2 / (3.0 + 5.0) kg
a = 2.0 kg x 9.81 m/s^2 / 8.0 kg
a = 2.45 m/s^2
Therefore, the resulting acceleration of the masses is 2.5 m/s^2 (option C).

A 30-Kg Mass and a 5