An object slides on a level floor.It slows and comes to a stop with a constant acceleration of magnitude 2.4 m/s².What is the coefficient of kinetic friction between the object and the floor? A)0.24 B)0.48 C)0.12 D)It is impossible to determine without knowing the mass of the object.

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Quizplus · Accepted Answer

The coefficient of kinetic friction is given by the equation:$$f_k = \mu_k * n$$where:* $f_k$ is the force of kinetic friction* $\mu_k$ is the coefficient of kinetic friction* $n$ is the normal forceIn this problem, the normal force is equal to the weight of the object:$$n = mg$$where:* $m$ is the mass of the object* $g$ is the acceleration due to gravityThe force of kinetic friction is equal to the mass of the object times the acceleration:$$f_k = ma$$where:* $a$ is the acceleration of the objectSubstituting these equations into the first equation, we get:$$\mu_k = \frac{ma}{mg} = \frac{a}{g}$$Plugging in the given values, we get:$$\mu_k = \frac{2.4 \ m/s^2}{9.8 \ m/s^2} = 0.24$$Therefore, the coefficient of kinetic friction is 0.24.

An Object Slides on a Level Floor