A 50-kg box is being pushed along a horizontal surface.The coefficient of static friction between the box and the ground is 0.65,and the coefficient of kinetic friction is 0.35.What horizontal force must be exerted on the box for it to accelerate at 1.2 m/s²? A)60 N B)120 N C)170 N D)230 N E)490 N

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Quizplus · Accepted Answer

To find the force needed to accelerate the box, first calculate the force of kinetic friction: F_friction = μ_k * m * g = 0.35 * 50 kg * 9.8 m/s² = 171.5 N. Then, calculate the net force required for the acceleration: F_net = m * a = 50 kg * 1.2 m/s² = 60 N. The total force needed is the sum of the frictional force and the net force: F_total = F_friction + F_net = 171.5 N + 60 N = 231.5 N, which rounds to 230 N.

A 50-Kg Box Is Being Pushed Along a Horizontal Surface