A 6.0-kg box slides down an inclined plane that makes an angle of 39° with the horizontal.If the coefficient of kinetic friction is 0.40,at what rate does the box accelerate down the slope? A)3.1 m/s² B)3.4 m/s² C)3.7 m/s² D)4.1 m/s²

Question

Quizplus · Accepted Answer

The correct answer is A because the acceleration of the box down the slope is given by a = g * sin(theta) - mu * g * cos(theta), where g is the acceleration due to gravity, theta is the angle of the incline, and mu is the coefficient of kinetic friction. Plugging in the given values, we get a = 9.8 m/s^2 * sin(39°) - 0.40 * 9.8 m/s^2 * cos(39°) = 3.1 m/s^2.

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