If 4.0 J of work are performed in stretching an ideal spring with a spring constant (force constant)of 2500 N/m,by what distance is the spring stretched?
A)3.2 cm
B)3.2 m
C)0.3 cm
D)5.7 m
E)5.7 cm

Question

Quizplus · Accepted Answer

The work done on a spring is given by the formula W = 0.5 * k * x^2, where W is the work done, k is the spring constant, and x is the distance stretched. Solving for x, we get x = sqrt(2W/k). Substituting W = 4.0 J and k = 2500 N/m, we find x = sqrt(2*4.0/2500) = 0.057 m = 5.7 cm.

If 40 J of Work Are Performed in Stretching an Ideal