If the work done to stretch an ideal spring by 4.0 cm is 6.0 J,what is the spring constant (force constant)of this spring?
A)300 N/m
B)3000 N/m
C)3500 N/m
D)7500 N/m
E)6000 N/m

Question

Quizplus · Accepted Answer

The formula for the potential energy stored in a spring is: 
PE = (1/2)kx^2 
where k is the spring constant and x is the displacement from equilibrium.

Given: 
PE = 6.0 J 
x = 4.0 cm = 0.04 m

Substituting the values, 
6.0 = (1/2)k(0.04)^2 
k = 7500 N/m

Therefore, the spring constant is 7500 N/m. Choice D is the correct answer.

If the Work Done to Stretch an Ideal Spring by 4.0