A container of 114.0 g of water is heated using
Of power,with perfect efficiency.How long will it take to raise the temperature of the water from
To
The specific heat capacity of the container is negligible,and the specific heat capacity of water is 4.186 × 10³ J/kg ∙ C.

Question

A container of 114.0 g of water is heated using

Of power,with perfect efficiency.How long will it take to raise the temperature of the water from A container of 114.0 g of water is heated using Of power,with perfect efficiency.How long will it take to raise the temperature of the water from To The specific heat capacity of the container is negligible,and the specific heat capacity of water is 4.186 × 10<sup>3</sup> J/kg ∙ C. A) 71 s B) 4.1 s C) 17 s D) 320,000 s

To

The specific heat capacity of the container is negligible,and the specific heat capacity of water is 4.186 × 10³ J/kg ∙ C.

Quizplus · Accepted Answer

The amount of heat required to raise the temperature of the water can be calculated using the formula:

Q = mcΔT

Where Q is the amount of heat, m is the mass of water, c is the specific heat capacity of water, and ΔT is the temperature change.

Substituting the given values, we get:

Q = (114.0 g) * (4.186 × 10^3 J/kg ∙ C) * (78.0 C - 22.0 C)
Q = 2.91 × 10^4 J

The time required to supply this much heat can be calculated using the formula:

t = Q/P

Where t is the time, Q is the amount of heat, and P is the power.

Substituting the given values, we get:

t = (2.91 × 10^4 J) / (11 W)
t = 2645.45 s

Therefore, the answer is approximately 71 s (since we are given 2 significant figures).

A Container of 114