A refrigerator has a coefficient of performance equal to 4.2.How much work must be done on the operating gas in the refrigerator in order to remove 250 J of heat from the interior compartment?
A)60 J
B)120 J
C)250 J
D)480 J
E)1050 J

Question

Quizplus · Accepted Answer

The coefficient of performance (COP) for a refrigerator is given by COP = Qc/W, where Qc is the heat removed from the cold reservoir (interior compartment) and W is the work done on the system. Given COP = 4.2 and Qc = 250 J, we can rearrange the formula to solve for W: W = Qc / COP = 250 J / 4.2 ≈ 60 J.

A Refrigerator Has a Coefficient of Performance Equal to 4