If we add 700 J of heat to 12 moles of an ideal monatomic gas at constant volume,what will be the change in temperature of the gas? (R = 8.31 J/mol ∙ K)
A)4.7 K
B)5.2 K
C)5.8 J
D)6.8 K
E)9.3 K

Question

Quizplus · Accepted Answer

The change in temperature can be calculated using the formula ΔQ = nCvΔT, where ΔQ is the heat added, n is the number of moles, Cv is the molar specific heat at constant volume for a monatomic gas (3/2 R), and ΔT is the change in temperature. Plugging in the values: 700 = 12 * (3/2 * 8.31) * ΔT, solving for ΔT gives approximately 4.7 K.

If We Add 700 J of Heat to 12 Moles