When the potential difference between the plates of an ideal air-filled parallel plate capacitor is 35 V,the electric field between the plates has a strength of 750 V/m.If the plate area is 4.0 × 10^-² m²,what is the capacitance of this capacitor? (ε₀ = 8.85 × 10^-12C²/N ∙ m²)

Question

Quizplus · Accepted Answer

Capacitance of a parallel plate capacitor is given by:

C = εA/d

where ε is the permittivity of air, A is the area of the plates and d is the distance between them.

Substituting the given values, we get:

C = (8.85 × 10^-12 N^-1.m^-2)(4.0 × 10^-2 m^2)/(750 V/m)

C = 3.74 × 10^-12 F

This is the capacitance of one plate, so the total capacitance of the parallel plate capacitor is:

Ctotal = 2C = 7.6 × 10^-12 F

Therefore, the best choice is B.

When the Potential Difference Between the Plates of an Ideal