The square plates of a 3000-pF parallel-plate capacitor measure 40 mm by 40 mm and are separated by a dielectric that is 0.29 mm thick and completely fills the region between the plates.What is the dielectric constant of the dielectric? (ε₀ = 8.85 × 10^-12C²/N ∙ m²)

Question

Quizplus · Accepted Answer

The dielectric constant (κ) can be calculated using the formula for capacitance: C = κε₀A/d. Rearranging for κ gives κ = Cd/(ε₀A). Substituting the given values: C = 3000 pF = 3000 × 10⁻¹² F, A = (0.04 m)², d = 0.29 × 10⁻³ m, and ε₀ = 8.85 × 10⁻¹² C²/N·m², we find κ ≈ 61.

The Square Plates of a 3000-PF Parallel-Plate Capacitor Measure 40