The primary coil of an ideal transformer has 600 turns and its secondary coil has 150 turns.If the current in the primary coil is 2 A,what is the current in its secondary coil?
A)8 A
B)1/2 A
C)1/4 A
D)2 A
E)4 A

Question

Quizplus · Accepted Answer

The current in the secondary coil can be found using the transformer equation $I_1/I_2 = N_2/N_1$, where $I_1$ and $I_2$ are the currents in the primary and secondary coils, respectively, and $N_1$ and $N_2$ are the number of turns in the primary and secondary coils, respectively. Substituting the given values, $2/I_2 = 150/600$, solving for $I_2$ gives $I_2 = 8$ A.

The Primary Coil of an Ideal Transformer Has 600 Turns