A series circuit has a 100-Ω resistor,a 0.100-μF capacitor,and a 2.00-mH inductor connected across a 120 V rms ac source operating at resonant frequency.What is the rms value of the voltage across the inductor?
A)170 V
B)150 V
C)120 V
D)54.0 V
E)533 V

Question

Quizplus · Accepted Answer

At resonance, the voltage across the inductor is maximum and is given by:$$V_L = I_L X_L = \frac{V_{rms}}{Z} X_L = \frac{V_{rms}}{\sqrt{R^2 + (X_L - X_C)^2}} X_L$$$$= \frac{120 V}{\sqrt{100^2 + (2\pi 60 Hz 	imes 2.00 mH - \frac{1}{2\pi 60 Hz 	imes 0.100 \mu F})^2}} (2\pi 60 Hz 	imes 2.00 mH)$$$$= 170 V$$

A Series Circuit Has a 100-Ω Resistor,a 0