A resistance of 55 Ω,a capacitor of capacitive reactance 30 Ω,and an inductor of inductive reactance 30 Ω are connected in series to a 110-V rms,60-Hz power source.What rms current flows in this circuit?
A)2.0 A
B)less than 2.0 A
C)more than 2.0 A
D)none of the given answers

Question

Quizplus · Accepted Answer

The total impedance (Z) in the circuit can be calculated using the formula Z = sqrt(R^2 + (XL - XC)^2), where R is the resistance, XL is the inductive reactance, and XC is the capacitive reactance. Here, R = 55 Ω, XL = 30 Ω, and XC = 30 Ω. Since XL = XC, the reactive parts cancel each other out, leaving Z = R = 55 Ω. The rms current (I) can then be found using Ohm's law, I = V/Z, where V is the rms voltage. Substituting the given values, I = 110 V / 55 Ω = 2.0 A.

A Resistance of 55 Ω,A Capacitor of Capacitive Reactance 30