Consider the nuclear reaction
N +
He →
O +
H.The known atomic masses are
N: 14.003074 u
He: 4.002603 u
H: 1.007825 u
O: 16.999131 u
What is the Q-value (or reaction energy) of this reaction? (1 u = 931.5 MeV/c²)

Question

Consider the nuclear reaction

N +

He →

O +

H.The known atomic masses are Consider the nuclear reaction N + He → O + H.The known atomic masses are N: 14.003074 u He: 4.002603 u H: 1.007825 u O: 16.999131 u What is the Q-value (or reaction energy) of this reaction? (1 u = 931.5 MeV/c2) A) 1.191 MeV B) -1.191 MeV C) 1.279 × 10-3 MeV D) -1.279 × 10-3 MeV

N: 14.003074 u Consider the nuclear reaction N + He → O + H.The known atomic masses are N: 14.003074 u He: 4.002603 u H: 1.007825 u O: 16.999131 u What is the Q-value (or reaction energy) of this reaction? (1 u = 931.5 MeV/c2) A) 1.191 MeV B) -1.191 MeV C) 1.279 × 10-3 MeV D) -1.279 × 10-3 MeV

He: 4.002603 u Consider the nuclear reaction N + He → O + H.The known atomic masses are N: 14.003074 u He: 4.002603 u H: 1.007825 u O: 16.999131 u What is the Q-value (or reaction energy) of this reaction? (1 u = 931.5 MeV/c2) A) 1.191 MeV B) -1.191 MeV C) 1.279 × 10-3 MeV D) -1.279 × 10-3 MeV

H: 1.007825 u Consider the nuclear reaction N + He → O + H.The known atomic masses are N: 14.003074 u He: 4.002603 u H: 1.007825 u O: 16.999131 u What is the Q-value (or reaction energy) of this reaction? (1 u = 931.5 MeV/c2) A) 1.191 MeV B) -1.191 MeV C) 1.279 × 10-3 MeV D) -1.279 × 10-3 MeV

O: 16.999131 u
What is the Q-value (or reaction energy) of this reaction? (1 u = 931.5 MeV/c²)

Quizplus · Accepted Answer

The Q-value (reaction energy) can be calculated using the formula:

Q = (m_initial - m_final - m_H) x c^2

where:
m_initial = mass of the initial reactants 
m_final = mass of the final products
m_H = mass of a hydrogen atom (proton)
c = speed of light

Plugging in the given values: 
m_initial = 14.003074 u + 4.002603 u = 18.005677 u 
m_final = 16.999131 u + 1.007825 u = 18.006956 u 
m_H = 1.007825 u 
c = 931.5 MeV/c^2

Q = (18.005677 u - 18.006956 u - 1.007825 u) x (931.5 MeV/c^2) 
Q = (-0.008104 u) x (931.5 MeV/c^2) 
Q = -7.547 MeV

Rounding to two significant figures, we get: 
Q = -7.5 MeV

Since the Q-value is negative, energy is released in this reaction. Therefore, the correct answer is B, -1.191 MeV, as it is the only negative value option.

Consider the Nuclear Reaction