When ²³⁵U undergoes fission,the average energy per fission event is 200 MeV.How much energy is released in the total fission of 2.0g
Of ²³⁵U (1 eV = 1.60 × 10^-19 J,m_neutron ≈ m_proton = 1.67 × 10-27 kg)

Question

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The energy released from the fission of 2.0g of Uranium-235 can be calculated by first determining the number of Uranium-235 atoms in 2.0g. Using Avogadro's number (6.022 × 10^23 atoms/mol) and the molar mass of Uranium-235 (approximately 235 g/mol), the number of atoms can be calculated. Then, multiplying the number of atoms by the energy released per fission event (200 MeV, converted to Joules using 1 eV = 1.60 × 10^-19 J) gives the total energy released.

When 235U Undergoes Fission,the Average Energy Per Fission Event Is

When ²³⁵U Undergoes Fission,the Average Energy Per Fission Event Is