A car is moving with a speed of 32.0 m/s. The driver sees an accident ahead and slams on the brakes, giving the car a deceleration of 3.50 m/s². How far does the car travel after the driver put on the brakes before it comes to a stop? A) 4.57 m B) 9.14 m C) 112 m D) 146 m E) 292 m

Question

Quizplus · Accepted Answer

We can use the kinematic equation: 
v^2 = u^2 + 2as
where v = 0 (final velocity is zero), u = 32.0 m/s (initial velocity), a = -3.50 m/s^2 (deceleration), and s is the distance traveled. 
Rearranging, 
s = (v^2 - u^2) / 2a = (0 - (32.0)^2) / (2(-3.50)) = 146 m. 
Therefore, the car travels 146 m before coming to a stop. 
The best choice is D.

A Car Is Moving with a Speed of 32