A car is traveling at 30.0 m/s when the driver suddenly applies the brakes, giving the car a constant deceleration. The car comes to a stop in a distance of 120.0 m. What was the deceleration of the car? A) 3.75 m/s² B) 4.00 m/s² C) 4.25 m/s² D) 4.50 m/s² E) 4.75 m/s²

Question

Quizplus · Accepted Answer

The correct answer is A because the deceleration of the car can be calculated using the formula: a = (v^2 - u^2) / 2s, where a is the deceleration, v is the final velocity (0 m/s), u is the initial velocity (30.0 m/s), and s is the distance traveled (120.0 m). Plugging in these values, we get: a = (0^2 - 30.0^2) / 2(120.0) = -3.75 m/s^2. The negative sign indicates that the car is decelerating.

A Car Is Traveling at 30