A ball is thrown at an angle 40.0° above the horizontal with an initial velocity of 28.0 m/s. What is the range of the ball?
A) 78.8 m
B) 59.8 m
C) 19.6 m
D) 37.8 m
E) None of the other choices is correct.

Question

Quizplus · Accepted Answer

The range of the ball can be calculated using the formula:
Range = (v^2/g) * sin(2θ)
where v = initial velocity, g = acceleration due to gravity, and θ = angle of projection

Plugging in the given values, we get:
Range = (28^2/9.8) * sin(80) ≈ 78.8 m

Therefore, the answer is choice A.

A Ball Is Thrown at an Angle 40