A diver exhales a bubble with a volume of 250 mL at a pressure of 2.4 atm and a temperature of 15 °C.What is the volume of the bubble when it reaches the surface where the pressure is 1.0 atm and the temperature is 27 °C?

Question

Quizplus · Accepted Answer

Using the combined gas law:

P1V1/T1 = P2V2/T2

Where:

P1 = 2.4 atm (initial pressure)
V1 = 250 mL (initial volume)
T1 = 15 °C + 273.15 = 288.15 K (initial temperature in Kelvin)
P2 = 1.0 atm (final pressure)
V2 = ? (final volume)
T2 = 27 °C + 273.15 = 300.15 K (final temperature in Kelvin)

Solving for V2:

V2 = (P1V1T2)/(P2T1)

V2 = (2.4 atm × 250 mL × 300.15 K)/(1.0 atm × 288.15 K)

V2 ≈ 630 mL

Therefore, the volume of the bubble when it reaches the surface is approximately 630 mL, which corresponds to choice (B).

A Diver Exhales a Bubble with a Volume of 250