What is the limiting reactant for the reaction below given that you start with 10.0 grams of Al and 19.0 grams of O₂?
Reaction: 4Al + 3O₂ → 2Al₂O₃

Question

What is the limiting reactant for the reaction below given that you start with 10.0 grams of Al and 19.0 grams of O₂? Reaction: 4Al + 3O₂ → 2Al₂O₃

Quizplus · Accepted Answer

To determine the limiting reactant, we first need to interpret the chemical formula correctly. "O₂" seems to be a formatting error, making it impossible to identify the compound accurately. However, assuming a typical reaction involving aluminum (Al) and another compound, we calculate the moles of each reactant and compare their ratios to the stoichiometry of the reaction. For Al (molar mass = 26.98 g/mol), 10.0 grams corresponds to 10.0 / 26.98 = 0.370 moles. Without the correct molar mass for the other reactant, we cannot perform an exact calculation, but the approach involves dividing the mass of the second reactant by its molar mass to find its moles, then comparing the mole ratio of Al to the other reactant with the 4:3 ratio from the reaction equation. The limiting reactant is the one present in less than the stoichiometric amount required for the reaction to proceed completely. Given the lack of specific information on the second reactant, a precise calculation cannot be made, but typically, this approach identifies the limiting reactant.

What Is the Limiting Reactant for the Reaction Below Given