How many moles of aluminum oxide are produced according to the reaction below given that you start with 10.0 grams of Al and 19.0 grams of O₂?
Reaction: 4Al + 3O₂ → 2Al₂O₃

Question

How many moles of aluminum oxide are produced according to the reaction below given that you start with 10.0 grams of Al and 19.0 grams of O₂? Reaction: 4Al + 3O₂ → 2Al₂O₃

Quizplus · Accepted Answer

First, calculate moles of Al (10.0 g / 26.98 g/mol = 0.371 mol) and O2 (19.0 g / 32.00 g/mol = 0.594 mol). The reaction requires 4 mol Al for every 3 mol O2. Al is the limiting reactant (0.371 mol Al requires 0.278 mol O2). Thus, 0.371 mol Al produces 0.185 mol Al2O3 (0.371 mol Al * (2 mol Al2O3 / 4 mol Al)).

How Many Moles of Aluminum Oxide Are Produced According to the Reaction