What is the excess reactant for the reaction below given that you start with 10.0 grams of Al and 19.0 grams of O₂?
Reaction: 4Al + 3O₂ → 2Al₂O₃

Question

What is the excess reactant for the reaction below given that you start with 10.0 grams of Al and 19.0 grams of O₂? Reaction: 4Al + 3O₂ → 2Al₂O₃

Quizplus · Accepted Answer

To determine the excess reactant, we must first determine the limiting reactant. We can do this by calculating the moles of each reactant: mol Al = 10.0 g / 26.98 g/mol = 0.371 mol mol O₂ = 19.0 g / 186.96 g/mol = 0.102 mol We can see that O₂ is the limiting reactant because it produces fewer moles of the product compared to Al. Therefore, Al is the excess reactant.

What Is the Excess Reactant for the Reaction Below Given