Refer to the following partial ANOVA results from Excel (some information is missing). ANOVA table $$\begin{array} { | l | c | c | c | c | c | }
\hline \text { Source } & \text { SS } & d f & M S & F & p \text {-value } \
\hline \text { Treatment } & 717.40 & 3 & & & .0442 \
\hline \text { Error } & & & 70.675 & & \
\hline \text { Total } & 1,848.20 & 19 & & & \
\hline
\end{array}$$ The MS (mean square) for the treatments is:
A)239.13.
B)106.88.
C)1,130.8.
D)impossible to ascertain from the information given.

Question

Refer to the following partial ANOVA results from Excel (some information is missing). ANOVA table $$\begin{array} { | l | c | c | c | c | c | } 
\hline \text { Source } & \text { SS } & d f & M S & F & p \text {-value } \
\hline \text { Treatment } & 717.40 & 3 & & & .0442 \
\hline \text { Error } & & & 70.675 & & \
\hline \text { Total } & 1,848.20 & 19 & & & \
\hline
\end{array}$$ The MS (mean square) for the treatments is:
A)239.13.
B)106.88.
C)1,130.8.
D)impossible to ascertain from the information given.

Quizplus · Accepted Answer

The MS (mean square) for treatments is calculated by dividing the SS (sum of squares) for treatments by its degrees of freedom (df). Thus, MS for treatments = 717.40 / 3 = 239.13.

Refer to the Following Partial ANOVA Results from Excel (Some