Refer to the following MegaStat output (some information is missing). The sample size was n = 24 in a one-factor ANOVA. $\text { Tukev simultaneous comparison t-values }$
$\begin{array}{|c|c|c|c|c|c|}
\hline &&\text { Med } 4 & \text { Med } 1& \text { Med } 3& \text { Med } 2\
&&133.2 & 140.7 & 141.7 & 145.2 \
\hline\text { Med } 4 &133.2&& & & \
\hline \text { Med } 1&140.7&1.78 & & & \
\hline \text { Med } 3&141.7&2.01 & 0.24 & & \
\hline\text { Med } 2&145.2&2.84 & 1.07 & 0.83 & \
\hline
\end{array}$ Which pairs of meds differ at ? = .05? Note: This question requires access to a Tukey table.
A)Med 1, Med 2
B)Med 2, Med 4
C)Med 3, Med 4
D)None of them.

Question

Quizplus · Accepted Answer

The Tukey test compares all possible pairs of means to find which ones are significantly different from each other. The critical value for a Tukey test depends on the chosen alpha level (α = .05), the number of groups, and the degrees of freedom for error. Without the exact critical value from a Tukey table, we rely on the provided t-values for the pairwise comparisons. The t-value for the pair Med 2 and Med 4 is 2.84, which is likely to exceed the critical value for significance at α = .05 given the sample size and typical critical values for Tukey tests. This suggests that Med 2 and Med 4 differ significantly from each other, while the other pairs do not show significant differences based on their lower t-values.

Refer to the Following MegaStat Output (Some Information Is Missing) Tukev simultaneous comparison t-values \text { Tukev simultaneous comparison t-values } Tukev simultaneous comparison t-values

Refer to the Following MegaStat Output (Some Information Is Missing) $\text { Tukev simultaneous comparison t-values }$