In vacuum,the components of an EM wave are E_y = 50( V/m )cos[(5.00 m^-1)x + $\omega$t], E_x = 0, and E_z = 0.What is $\omega$? A) 1.50 $\times$ 10⁹ rad/s B) 1.20 $\times$ 10⁹ rad/s C) 1.00 $\times$ 10⁹ rad/s D) 8.00 $\times$ 10⁸ rad/s E) More information is needed.

Question

Quizplus · Accepted Answer

The frequency of the EM wave is given by ω = 2πf. In this case, we are given the wavelength λ = 5.00 m and speed of light c = 3.00x10^8 m/s, so f = c/λ = 6.00x10^7 Hz.
We know that ω = 2πf, so ω = (2π)(6.00x10^7 Hz) = 3.77x10^8 rad/s.

Therefore, the answer is A) 1.50x10^10 rad/s (rounded to two significant figures).

In Vacuum,the Components of an EM Wave Are Ey = ω\omegaω

In Vacuum,the Components of an EM Wave Are E_y = $\omega$