In vacuum,the components of an EM wave are E_y = 50( V/m )cos[(5.0 m^-1)x + $\omega$t], E_x = 0, and E_z = 0.What is the amplitude of the magnetic field for this wave? A) 5.00 $\times$ 10^-7 T B) 1.67 $\times$ 10^-7 T C) 2.00 $\times$ 10^-7 T D) 1.50 $\times$ 10^-6 T E) 1.33 $\times$ 10^-6 T

Question

Quizplus · Accepted Answer

The amplitude of the magnetic field (B) is related to the amplitude of the electric field (E) by the equation B = E/c, where c is the speed of light in vacuum (approximately 3.00 * 10^8 m/s). For E = 50 V/m, B = 50 / (3.00 * 10^8) = 1.67 * 10^-7 T.

In Vacuum,the Components of an EM Wave Are Ey = ω\omegaω

In Vacuum,the Components of an EM Wave Are E_y = $\omega$