A metal rod of length 2.0 m is moved at 6.0 m/s in a direction perpendicular to its length.A 5.0 m T magnetic field is perpendicular to both the rod and its velocity.What is the potential difference between the ends of the rod?
A) 12 mV
B) 60 mV
C) 30 mV
D) 15 mV
E) 0

Question

Quizplus · Accepted Answer

The potential difference (emf) induced in the rod can be calculated using the formula emf = B * v * L, where B is the magnetic field strength, v is the velocity, and L is the length of the rod. Substituting the given values: emf = 5.0 T * 6.0 m/s * 2.0 m = 60 V or 60 mV.

A Metal Rod of Length 2