A 20 turn coil of area 10 cm² is placed in a magnetic field so that the normal to its area is in the direction of the field.If the field has a value of 0.25 T,what is the total flux through the coil? A) 0.0 B) 5.0 $\times$ 10^-3 T·m² C) 25 $\times$ 10^-5 T·m² D) 50 T · m² E) 25 T · m²

Question

Quizplus · Accepted Answer

The magnetic flux through a coil is given by the product of the magnetic field strength, the area of the coil, and the cosine of the angle between the normal to the coil and the magnetic field. In this case, the normal to the coil is in the direction of the magnetic field, so the cosine of the angle is 1. Therefore, the magnetic flux through the coil is:$$\Phi = BA\cos	heta = (0.25 	ext{ T})(10 	ext{ cm}^2)(1) = 5.0 	imes 10^{-3} 	ext{ T}\cdot	ext{m}^2$$

A 20 Turn Coil of Area 10 Cm2 Is Placed ×\times×

A 20 Turn Coil of Area 10 Cm² Is Placed $\times$