A flat coil has a maximum flux 4.0 $\times$ 10^-3 T·m² through it as its area is perpendicular to a uniform magnetic field.When the coil is rotated 60$^{\circ}$(so that its normal makes a 60$^{\circ}$angle with the field),what is the flux through it? A) 4.0 $\times$ 10^-3 T·m² B) 8.0 $\times$ 10^-3 T·m² C) 3.5 $\times$ 10^-3 T·m² D) 2.0 $\times$ 10^-3 T·m² E) 6.9 $\times$ 10^-3 T·m²

Question

Quizplus · Accepted Answer

The magnetic flux through the coil is given by Φ = Φ₀ * cos(θ), where Φ₀ is the maximum flux and θ is the angle between the normal to the coil and the magnetic field. Here, Φ₀ = 4.0 * 10⁻³ T·m² and θ = 60°. So, Φ = 4.0 * 10⁻³ * cos(60°) = 4.0 * 10⁻³ * 0.5 = 2.0 * 10⁻³ T·m².

A Flat Coil Has a Maximum Flux 4 ×\times× 10-3 T·m2 Through It as Its Area Is Perpendicular to T·m2

A Flat Coil Has a Maximum Flux 4 $\times$ 10^-3 T·m² Through It as Its Area Is Perpendicular to T·m²