The magnetic field in a cyclotron is 0.50 T.What is the radius of the vacuum chamber for a maximum proton velocity of 1.0 $\times$ 10⁷ m/s? A) 0.11 m B) 1.2 m C) 0.21 m D) 0.013 m

Question

Quizplus · Accepted Answer

The radius of the vacuum chamber can be found using the formula:
r = mv / (qB)
where:
m = mass of the particle (proton) = 1.67 x 10^-27 kg
v = maximum velocity of the particle = 1.0 x 10^7 m/s
q = charge of the particle = 1.60 x 10^-19 C
B = magnetic field strength = 0.50 T

Plugging in the values:
r = (1.67 x 10^-27 kg)(1.0 x 10^7 m/s) / (1.60 x 10^-19 C)(0.50 T)
r = 0.21 m

Therefore, the answer is choice C.

The Magnetic Field in a Cyclotron Is 0 ×\times× 107 M/s? A) 0

The Magnetic Field in a Cyclotron Is 0 $\times$ 10⁷ M/s?
A) 0