A 3.0 cm section of a horizontal wire carrying a 6.7 A current from east to west is placed in a north to south 0.42 T magnetic field in the lab.What is the magnitude of the force on the 3.0 cm section of the wire?
A) 0.084 N
B) 0.17 N
C) 0.25 N
D) 0.0017 N
E) 0.0025 N

Question

Quizplus · Accepted Answer

The force on a current-carrying wire in a magnetic field is given by F = I * L * B * sin(θ). Here, I = 6.7 A, L = 0.03 m, B = 0.42 T, and θ = 90° (since the current is perpendicular to the magnetic field). Thus, F = 6.7 * 0.03 * 0.42 * 1 = 0.084 N.

A 30 Cm Section of a Horizontal Wire Carrying a 6