What area plates would a parallel plate 1.0 F capacitor have with a plate separation of 0.10 mm and a dielectric of constant 10?

Question

Quizplus · Accepted Answer

The capacitance of a parallel plate capacitor is given by:

C = εA/d

where ε is the permittivity of the dielectric material, A is the area of the plates and d is the distance between them.

Substituting the given values, we have:

C = (10)(A)/(0.1 mm) = 100A F

To obtain a capacitance of 1 F, we need:

A = 1/100 m^2 = 10,000 cm^2

Therefore, the answer is D, which is equivalent to 1.1 x 10^-9 m^2 or 11,000 cm^2.

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