The electron orbiting the proton in the hydrogen atom is at a distance of 5.3 $\times$ 10^-9 m.What is the magnitude of the electric force between the proton and the electron? A) 1.6 $\times$ 10^-19 N B) 2.7 $\times$ 10² N C) 4.3 $\times$ 10^-17 N D) 8.2 $\times$ 10^-12 N E) 2.7 $\times$ 10^-2 N

Question

Quizplus · Accepted Answer

The magnitude of electric force between the proton and the electron can be calculated using Coulomb's law:

F = (k*q1*q2)/r^2

where k is Coulomb's constant (9x10^9 N*m^2/C^2), q1 and q2 are the charges of the two particles (in this case, +1.6x10^-19 C for the proton and -1.6x10^-19 C for the electron), and r is their distance apart (5.3x10^-11 m).

Substituting these values into the equation gives:

F = (9x10^9)*(1.6x10^-19)*(-1.6x10^-19)/(5.3x10^-11)^2

Simplifying, we get:

F = 8.24x10^-12 N

Which can be written in scientific notation as:

F = 8.2x10^-12 N

Therefore, the best choice is D, which is the closest to the calculated value of the electric force.

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