A point charge of 3.00 $ \mu$C is located on the y-axis at y = 4.0 m,another point charge of 6.0 $ \mu$C is located on the x-axis at x = 5.0 m,and a third charge of 7.2 $ \mu$C is located at (5.0 m,4.0 m).What is the magnitude of the force on the 7.2 $ \mu$C charge? A) 1.2 $\times$ 10^-2 N B) 1.6 $\times$ 10^-2 N C) 1.9 $\times$ 10^-2 N D) 2.6 $\times$ 10^-2 N E) 3.3 $\times$ 10^-2 N

Question

Quizplus · Accepted Answer

The force on the 7.2 µC charge can be found using Coulomb's Law:
F = k*q1*q2/r^2
where k is the Coulomb constant, q1 and q2 are the charges, and r is the distance between the charges.

Using this formula, we can find the forces between the 7.2 µC charge and the other two charges:

F1 = k*(7.2*10^-6)*(3*10^-6)/(5-4)^2 = 2.304*10^-2 N
F2 = k*(7.2*10^-6)*(6*10^-6)/(5-0)^2 = 6.912*10^-3 N

The force between the 7.2 µC charge and the other two charges is the vector sum of the forces F1 and F2, which can be found using the Pythagorean theorem:
F = sqrt(F1^2 + F2^2) = 2.609*10^-2 N

Therefore, the magnitude of the force on the 7.2 µC charge is 2.6*10^-2 N, which is closest to choice D.

A Point Charge of 3 μ \muμ C Is Located on the Y-Axis at Y = 4

A Point Charge of 3 $\mu$ C Is Located on the Y-Axis at Y = 4