Water falls a distance of 50.0 meters.The specific heat of water is 1.00 cal/gm$^{\circ}$C.What is the increase in temperature of the water after the fall,in$^{\circ}$C?

Question

Quizplus · Accepted Answer

The potential energy lost by the water is converted into heat energy, which increases the temperature. Using the formula mgh = mcΔT, where g = 9.8 m/s², h = 50 m, and specific heat = 1 cal/g°C = 4.18 J/g°C, we find ΔT = gh/c = (9.8 * 50) / 4.18 ≈ 0.12°C.

Water Falls a Distance of 50 ∘^{\circ}∘ CWhat Is the Increase in Temperature of the Water After

Water Falls a Distance of 50 $^{\circ}$ CWhat Is the Increase in Temperature of the Water After