A 100 g glass container contains 250 g of water at 15.0$^{\circ}$C.A 100 g piece of unknown material at 100$^{\circ}$C is added to the water in the container.The final temperature of the mixture is 19.0$^{\circ}$C.What is the specific heat of the unknown material in J/kg $^{\circ}$C? (specific heat of water = 4186 J/kg $^{\circ}$C, specific heat of glass = 837.2 J/kg $^{\circ}$C)

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The Answer of A 100 g glass container contains 250 g of water at 15.0$^{\circ}$C.A 100 g piece of unknown material at 100$^{\circ}$C is added to the water in the container.The final temperature of the mixture is 19.0$^{\circ}$C.What is the specific heat of the unknown material in J/kg $^{\circ}$C? (specific heat of water = 4186 J/kg $^{\circ}$C, specific heat of glass = 837.2 J/kg $^{\circ}$C)

A 100 G Glass Container Contains 250 G of Water ∘^{\circ}∘

A 100 G Glass Container Contains 250 G of Water $^{\circ}$