The specific heat of ice is 2.100 kJ/kg $^{\circ}$C,the heat of fusion for ice at 0$^{\circ}$C is 333.7 kJ/kg,the specific heat of water 4.186 kJ/kg$^{\circ}$C,the heat of vaporization of water at 100.0$^{\circ}$C is 2,256 kJ/kg,and the specific heat of steam is 2.020 kJ/kg $^{\circ}$C.What is the final equilibrium temperature when 20.00 grams of ice at -15.0$^{\circ}$C is mixed with 5.000 grams of steam at 120.0$^{\circ}$C?

Question

Quizplus · Accepted Answer

The energy calculations involve heating the ice to 0°C, melting it, heating the resulting water to the final temperature, cooling the steam to 100°C, condensing it, and cooling the resulting water to the final temperature. Solving the energy balance equation gives the final equilibrium temperature as 59.92°C.

The Specific Heat of Ice Is 2 ∘^{\circ}∘ C,the Heat of Fusion for Ice at 0

The Specific Heat of Ice Is 2 $^{\circ}$ C,the Heat of Fusion for Ice at 0