A metal rod is placed between two temperature sources so that heat can flow between them.One temperature is 90.0$^{\circ}$C and the other temperature is 25.0$^{\circ}$C.The length of the rod is 30.0 cm and the cross sectional area is 10.0 cm².If 15.0 watts of heat flows between the hot temperature and the cold temperature,then what is the coefficient of thermal conductivity for the metal?

Question

Quizplus · Accepted Answer

The formula for heat conduction is $ Q = \frac{k \cdot A \cdot \Delta T}{L} $. Rearranging for $ k $, we get $ k = \frac{Q \cdot L}{A \cdot \Delta T} $. Substituting the given values: $ Q = 15.0 $ W, $ L = 0.3 $ m, $ A = 0.001 $ m$^2$, and $ \Delta T = 65 $°C, we find $ k = \frac{15.0 \times 0.3}{0.001 \times 65} = 69.2 $ W/m.°C.

A Metal Rod Is Placed Between Two Temperature Sources So ∘^{\circ}∘

A Metal Rod Is Placed Between Two Temperature Sources So $^{\circ}$