2.00 moles of an ideal gas with a volume of 4.00 liters and a temperature of 0$^{\circ}$C is mixed with 1.00 mole of an ideal gas with a volume of 3.00 liters and a temperature of 100$^{\circ}$C.The volume of the mixture is 5.00 liters.What is the N/V of the mixture? A) 1.98 $\times$ 10²⁶ m^-3 B) 2.02 $\times$ 10²⁶ m^-3 C) 2.56 $\times$ 10²⁶ m^-3 D) 3.61 $\times$ 10²⁶ m^-3 E) 4.00 $\times$ 10²⁶ m^-3

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The Answer of 2.00 moles of an ideal gas with a volume of 4.00 liters and a temperature of 0$^{\circ}$C is mixed with 1.00 mole of an ideal gas with a volume of 3.00 liters and a temperature of 100$^{\circ}$C.The volume of the mixture is 5.00 liters.What is the N/V of the mixture? A) 1.98 $\times$ 10²⁶ m^-3 B) 2.02 $\times$ 10²⁶ m^-3 C) 2.56 $\times$ 10²⁶ m^-3 D) 3.61 $\times$ 10²⁶ m^-3 E) 4.00 $\times$ 10²⁶ m^-3

200 Moles of an Ideal Gas with a Volume of 4.00