2.00 moles of an ideal gas at standard temperature and volume changes its temperature by 1$^{\circ}$C.What is the change in the pressure?
A) 371 Pa
B) 323 Pa
C) 301 Pa
D) 298 Pa
E) 273 Pa

Question

Quizplus · Accepted Answer

The change in pressure can be calculated using the ideal gas law. At standard temperature and pressure (STP), 1 mole of an ideal gas occupies 22.4 L at 273 K and 1 atm. For 2 moles, the volume is 44.8 L. Using the formula $ \Delta P = \frac{nR\Delta T}{V} $, where $ n = 2 $ moles, $ R = 8.314 \, \text{J/mol K} $, $ \Delta T = 1 \, \text{K} $, and $ V = 44.8 \, \text{L} = 0.0448 \, \text{m}^3 $, the change in pressure is approximately 371 Pa.

200 Moles of an Ideal Gas at Standard Temperature and Volume