A copper ball with a diameter of 5.00 cm is subjected to a pressure of 2.50 $\times$ 10⁶ Pa.The bulk modulus for copper is 14.00 $\times$ 10¹⁰ N/m².What is the change in the volume? A) 1.01 $\times$ 10^-3 cm³ B) 1.17 $\times$ 10^-3 cm³ C) 1.20 $\times$ 10^-3 cm³ D) 1.58 $\times$ 10^-3 cm³ E) 1.70 $\times$ 10^-3 cm³

Question

Quizplus · Accepted Answer

The change in volume can be calculated using the formula ΔV = - (ΔP * V) / B, where ΔP is the pressure change, V is the initial volume, and B is the bulk modulus. The initial volume V of the sphere is (4/3)πr³, where r is the radius (2.5 cm). Convert the volume to m³, calculate ΔV, and convert back to cm³. The correct answer is approximately 1.17 * 10⁻³ cm³.

A Copper Ball with a Diameter of 5 ×\times× 106 Pa ×\times×

A Copper Ball with a Diameter of 5 $\times$ 10⁶ Pa $\times$