A 2.00 kg mass is connected to a spring with a spring constant of 900 N/m.The displacement is given by the expression x(t) = 12.0 cm sin($\omega$ t).What is the frequency of the simple harmonic motion?
A) 5.02 Hz
B) 4.21 Hz
C) 3.38 Hz
D) 2.56 Hz
E) 2.05 Hz

Question

Quizplus · Accepted Answer

The general equation for the frequency of a mass-spring system is given by f = 1/(2π)√(k/m), where k is the spring constant and m is the mass. Plugging in the given values, we get f = 1/(2π)√(900/2) = 3.38 Hz. Note that the given displacement expression is not needed to solve for the frequency.

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